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let f be a differentiable function such that f(3)=2 and f'(3)=5
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manish56
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Let f be a differentiable function such that f(3) = 2 and f'(3) = 5. If the tangent line to the graph of f at x = 3 is used to find an approximation to a zero of f, that approximation is?
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megha00
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y=mx+b f'(3)=5 means m=5
y=5x+b but f(3)=2 means
2=5*3+b, or b= -13
tangent line y= 5x-13
so the zero is 0=5x-13 x=13/5
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