Below you will find MCQ Questions of Chapter 1 Real Numbers Class 10 Maths that will help you in gaining good marks in the examinations and also cracking competitive exams. These Class 10 MCQ Questions with answers will widen your skills and understand concepts in a better manner.
MCQ Questions for Class 10 Maths Chapter 1 Real Numbers with Answers
1. If d is the HCF of 56 and 72, then values of x,y satisfying d = 56 x+72y :
(a) x = 3, y = −4
(b) x = −4,y = 3
(c) x = 4,y = −3
(d) x = −3,y = 4
► (c) x = 4,y = −3
2. If two positive integers a and b are written as a = x^{3}y^{2} and b = xy^{3}, where x, y are prime numbers, then LCM(a, b) is
(a) xy
(b) xy^{2}
(c) x^{3}y^{3}
(d) x^{2}y^{2}
► (c) x^{3}y^{3}
3. Every positive odd integer is of the form ________ where ‘q’ is some integer.
(a) 3q + 1
(b) 5q + 1
(c) 2q + 1
(d) 2q + 2
► (c) 2q + 1
4. If HCF (a, b) = 12 and a × b = 1800 then LCM (a, b) is
(a) 3600
(b) 900
(c) 150
(d) 90
► (c) 150
5. The decimal expansion of n is
(a) terminating
(b) non-terminating and non-recurring
(c) non-terminating and recurring
(d) does not exist.
► (b) non-terminating and non-recurring
6. The HCF and LCM of two numbers is 9 and 459 respectively. If one of the number is 27, then the other number is
(a) 459
(b) 153
(c) 135
(d) 150
► (b) 153
7. Two natural numbers whose sum is 85 and the least common multiple is 102 are:
(a) 30 and 55
(b) 17 and 68
(c) 35 and 55
(d) 51 and 34
► (d) 51 and 34
8. The largest number which divides 70 and 125 leaving remainders 5 and 8 respectively is
(a) 13
(b) 65
(c) 875
(d) 1750
► (a) 13
9. Find the greatest number of 5 digits, that will give us remainder of 5, when divided by 8 and 9 respectively.
(a) 99921
(b) 99931
(c) 99941
(d) 99951
► (c) 99941
10. If A = 2n + 13, B = n + 7 where n is a natural number then HCF of A and B
(a) 2
(b) 1
(c) 3
(d) 4
► (b) 1
11. If HCF(a, b) = 12 and a × b = 1800, then LCM(a, b) is
(a) 150
(b) 90
(c) 900
(d) 1800
► (a) 150
12. The product of two consecutive integers is divisible by
(a) 2
(b) 3
(c) 5
(d) 7
► (a) 2
13. The least perfect square number which is divisible by 3, 4, 5, 6 and 8 is
(a) 900
(b) 1200
(c) 2500
(d) 3600
► (d) 3600
14. If 112 = q×6+r, then the possible values of r are:
(a) 2, 3, 5
(b) 0, 1, 2, 3, 4, 5
(c) 1, 2, 3, 4
(d) 0, 1, 2, 3
► (b) 0, 1, 2, 3, 4, 5