Find the zeroes of the polynomial p(x)= (x – 2)^{2} – (x+ 2)^{2}.
Given, polynomial is p(x) = (x – 2)^{2} – (x+ 2)^{2}For zeroes of polynomial, put p(x) = 0(x – 2)^{2} – (x+ 2)^{2 }= 0(x-2 + x+2)(x-2-x-2) = 0 [using identity, a^{2}-b^{2} =(a-b)(a + b)] ⇒ (2x)(-4) = 0