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A rhombus whose diagonals are 4 cm and 6 cm in lengths.

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We know that, all sides of a rhombus are equal and the diagonals of a rhombus are perpendicular bisectors of one another. So, to construct a rhombus whose diagonals are 4 cm and 6 cm use the following steps.
1.Draw the diagonal say AC = 4 cm
2.Taking A and C as centres and radius more than ½ AC draw arcs on both sides of the line segment AC to intersect each other.
3.Cut both arcs intersect each other at P and Q, then join PQ.
4.Let PQ intersect AC at the point O. Thus, PQ is perpendicular bisector of AC.
5.Cut off 3 cm lengths from OP and OQ, then we get points B and D.
6.Now, join AB, BC, CD, and DA .
Thus, ABCD is the required rhombus.

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