Construct a traingle ABC in which BC=7.5cm angle B=45° and AC-AB=2.5cm

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asked Feb 4, 2018 in Board Exams by Shiwani r h (10 points)

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answered Feb 4, 2018 by Shabadpreet Basic (25 points)
1. Draw the base BC 7.5 cm and at point B make an angle say XBC of 45 degree.
2. Cut line segment BD equal to AC - BC (2.5 cm) from line BX extended on opiate side of BC.
3. Join DC and draw perpendicular bisector, say PQ of DC.
4. Let PQ intersect BX at A. Join AC.
 Thus, ABC is the required triangle.

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