If 4 g of NaOH dissolves in 36 g of H20, calculate the mole fraction of each component in the solution.

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asked Mar 5, 2018 in Class XI Chemistry by nikita74 (-1,032 points)

If 4 g of NaOH dissolves in 36 g of H20, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1 g mL-1). 

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answered Mar 5, 2018 by vijay Premium (530 points)

Mole fraction of H2O
= No.of moles of H2O/Total No.of moles (H2O + NaOH)
No. of moles of H2O = 36/18 = 2 moles
No. of moles NaOH = 4/40 = 0.1 mol
Total number of moles = 2+0.1 = 2.1
Mole fraction of H2O = 2/2.1 = 0.952
Mole fraction of NaOH = 0.1/2.1 = 0.048
Mass of solution
= Mass of H2O + Mass of NaOH = 36 + 4 = 40 g
Volume of solution = 40/1 = 40 mL
Molarity = No.of moles of solute/Volume of solution in L
= 0.1/0.04L = 2.5M 
  

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