There are two circles x2+y2=9 and x2+y2-8x-6y+n2=0

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asked Aug 3, 2018 in Class XII Maths by Gaurav sahu Basic (34 points)

There are two circles x2+y2=9 and x2+y2-8x-6y+n2=0. n belongs to z. If the two circles have exactly two common tangents, then the number of possible values of n is

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