P(t)=2+t+2t2-t3 then the values of p(0),p(1),p(2) are respectively

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asked Sep 28, 2018 in Class XII Maths by 9133191192 (15 points)

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answered Sep 30, 2018 by sneha25 Pro (115 points)
P(t)=2+t+2t2-t3 then the values of p(0),p(1),p(2) are respectively

p(t)=2+t+2t2-t3
p(0)=2+0+2*0*2-0*3
       =2

p(1)=2+1+2*1*2-1*3
       =4

p(2)=2+2+2*2*2-2*3
        =9

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