Find the area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm.
Area of isosceles triangle = a/4(√4b^{2} - a^{2}) = 2/4(√4.4^{2 }- 2^{2})
= 2/4 x √60 = 2/4 x 2√15 = √15 cm^{2}.