Show that four point (1,0), (2,-7), (8,1), and (9,-6) are concyclic

0 votes
1 view

Please log in or register to answer this question.

1 Answer

0 votes
answered Nov 25, 2018 by Amjid42 Basic (24 points)

We can prove this by using standard equation of circle.

The standard equation of the of a circle x2+y2+dx+ey+f=0

Put points (1,0) ,(2,-7) ,(9,-6) in equations of circle, we get three equations respectively.

1+d+f=0 , 

2d-7e+f=-53 ,

9d-6e+f=-117

Now after solving these equations, we get d= -10, e= 6, f=9.

For the proof of the concyclicity, we have to form the standard equation and then we have to check whether the fourth point satisfy the standard equation or not if it will satisfy the equation then these points are concyclic otherwise not.
Thus eqn. of circle is x2+y2-10x+6y+9=0
Put (8,1) in this equation =82+12-10*8+6*1+9
= 0

Thus all points are coincyclic.

Related questions

...