# A coolie carries a load of 30 kgf through a distance of 500 m in 5 minutes while another coolie B carries the same load through the same distance in 10 minutes.

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asked Dec 5, 2018

A coolie carries a load of 30 kgf through a distance of 500 m in 5 minutes while another coolie B carries the same load through the same distance in 10 minutes. Compare the (i) work done, and (ii) power developed. (Take: g = 10md-2)

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answered Dec 5, 2018 by (-4,333 points)

Given : F = 30 kgf = 30 x 10 N = 300 N, d = 500 m

For coolie A, work done W = F x d = 300 x 500 = 150,000 J.

Time t= 5 minute = 5 x 60s = 300s

∴ Power developed by P= W1/t = 150,000/300 = 500 Js-1

For coolie B, work done W2  = F x d = 3000 x 500 = 150,000 J

Time t= 10 minutes = 10 x 60s = 600s

∴ Power developed by P= W2/t2 = 150,000/600 = 250 Js-

(i) W1/W= 150,000/150,000 = 1/1.

(ii) P1/P= 500/250 = 1/2.

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