How fluorine can show plus one Oxidation state in HOF compound

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answered Dec 8, 2018 by Amresh Pro (116 points)
HOF
↑ ↑ ↑
1,2,x
↑ ↑ ↑
+ -  ?

Let the oxidation no. of flourine in HOF be x.

Now as the compound don't have any net charge we can write,
1-2+x=0
So, x=1
Therefore the oxidation no. of Flourine in HOF is 1.

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