A machine is driven by a 50 kg mass falling at a rate of 10.0 m in 5s.

0 votes
1 view
asked 6 days ago in Class X Science by priya12 (-10,126 points)

A machine is driven by a 50 kg mass falling at a rate of 10.0 m in 5s. It lifts n load of 250 kgf. Taking the force of gravity on 1 kg mass as 10 N. Calculate the power input to the machine. If the efficiency of the machine is 60%, find the height to which the load is raised in 5s.

Please log in or register to answer this question.

1 Answer

0 votes
answered 6 days ago by muskan15 (-1,113 points)

Given : Effort E = 50 kgf = 50 x 10 N = 500 N, dE  = 10.0 m, t = 5s

L = 250 kgf = 250 x 10 N = 2500 N, efficiency = 60% = 0.6

Power  input to the machine = Effort  x  Displacement of effort/Time

= 500 x 10.0/5 = 1000 W.

Let the load is raised to a height dL in 5s, then

Efficiency = Power output/ Power input = L x (dL/t)/E x (dE/t)

Or  0.6 = 2500 x d1/500 x 10

Or  dL = 500 x 10 x 0.6/2500 = 1.2 m.

Related questions

0 votes
1 answer
...