Five years ago, a woman’s age was the square of her son’s age.

0 votes
1 view
asked Feb 8 in Class X Maths by navnit40 (-2,514 points)

Five years ago, a woman’s age was the square of her son’s age. Ten years later her age will be twice that of her son’s age. Find:
(i) The age of the son five years ago.
(ii) The present age of the woman.

Please log in or register to answer this question.

1 Answer

0 votes
answered Feb 8 by priya12 (-11,078 points)

Let the age of son be x  years five years ago.

∴  Mother’s  age be x2 years five years ago.

After ten years son’s age be (x + 15) years and woman’s age be (x2 + 15)

Given   x2 + 15 = 2(x + 15)

x2 + 15 = 2x + 30

x2 – 2x – 15 = 0

(x – 5)(x + 3) = 0

x = 5

Or   x = - 3 (not possible)

∴   Son’s age five  years ago = 5 years

Woman’ present age = 25 + 5

 = 30 years.

Related questions

...