Let the ten’s digit be x, then unit’s digits = (14/x)
Then, the number is (10x + 14/x)
When 45 is added to the number, the digits get interchanged.
∴ 10x + 14/x + 45 = 10 × 14/x + x
⇒ x2 + 5x – 14 = 0
⇒ (x+ 7)(x – 2) = 0
⇒ x = 2
And x = - 7 (inadmissible)
Hence, the number is (10x + 14/x)
= (10 × 2 + 14/2)
= 27