Solve the quadratic equation: 4√5x^{2} + 7x - 3√5 = 0
The given equation is
4√5x^{2} + 7x - 3√5 = 0
⇒ 4√5x^{2} + 12x – 5x - 3√5 = 0
⇒ 4x(√5x + 3) - √5(√5x + 3) = 0
⇒ (√5x + 3)(4x - √5) = 0
⇒ √5x + 3 = 0 or 4x - √5 = 0
⇒ √5x = - 3 and 4x = √5
⇒ x = - 3/√5 and x = √5/4
So x = - 3/√5, √5/4