Given : BC = 5 cm, BP = 4 cm and ∠PBC = 45 ̊.
Steps of construction :
1.Construct ΔBCP with BC = 5 cm, BP = 4 cm and ∠PBC = 45 ̊.
2.Draw perpendiculars BE and CF and B and C respectively.
3.Draw perpendicular from on CF meeting CF in K.
4.Cut CD from CF, such that CK = KD.
5. Cut BA from BE, such that BA = CD.
Hence, ABCD is the required rectangle and AB = 5.7 cm.