(i) Plot the points A(1, 1), B(5, 3) and C(2, 7) as shown.
(ii) Join AB. Draw right bisector L of AB. Then , L is the locus of points equidistant from A and B.
(iii) Join AC. Draw bisector m of ∠CAB. Then, m is the locus of the points equidistant from AB and AC.
(iv) The point of intersection P of right bisector of AB and angle bisector of ∠CAB is the point such that PA = PB and P is equidistant from AB and AC.
(v) On measuring PA = 2.5 cm.