Construct an angle PQR = 45˚.

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asked Mar 14 in Class X Maths by priya12 (-11,279 points)

Construct an angle PQR = 45˚. Mark a point S on QR such that QS = 4.5 cm. Construct a circle to touch PQ at Q and also to pass through S.

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answered Mar 14 by muskan15 (-2,329 points)

Steps of construction :

(i) Draw  PQX = 90˚

(ii) Bisect PQX  and draw PQR = 45˚

(iii) Cut off QS = 4.5 cm from QR.

(iv) bisector of QS and it is intersect of QX at O.

(v) With O as centre and radius = OQ (or OS draw the required circle).

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