Only ruler and compass may be used in this question.

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asked Mar 14 in Class X Maths by aditya23 (-1,379 points)

(a) Only ruler and compass may be used in this question. All contraction lines and arcs must be clearly shown and be of sufficient length and clarity to permit assessment.

(i) Construct a ABC, such that AB = AC = 7 cm and BC = 5 cm.

(ii) Construct AD, the perpendicular bisector of BC.

(iii) Draw a circle with centre A and radius 3 cm. Let this circle cut AD at P.

(iv) Construct another circle, to touch the circle with centre A, externally at P, and pass through B and C.

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1 Answer

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answered Mar 14 by navnit40 (-3,330 points)

Steps of construction :

(i) (1) Draw BC = 5 cm.

(2) With B and C as centres draw rwo arcs to length 7 cm cutting each othr at A.

(3) Join AB and AC.

(4) Then ABC is required triangle.

(ii) Draw AD, the right bisector of BC.

(iii) With A as center and radius 3 cm draw a circle meeting AD in P.

(iv) (1) Join BP and CP.

(2) Draw the right bisector of CP meeting AD in O.

(3) With O as centre and radius  equal to OP draw the required circle, passing through B and C.

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