Steps of construction :
1.Draw a line segment BC = 3 cm and make ∠CBP = 45˚.
2. Construct EB ⊥ BP.
3. Draw the perpendicular bisector of BC its intersecting BE in O and BC in D.
4. Draw a circle taking O as centre and OB as radius.
5. Now with D as centre and radius = 3.5 cm draw arcs of the circle intersecting the above drawn circle in A and A’.
6. Join AB, AC and A’B, A’C. Then the △s, ABC and A’BC are the required triangles.