In an equilateral △ABC of side 14 cm, side BC is the diameter of a semi-circle as shown in the figure below.

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asked Mar 18 in Class X Maths by muskan15 (-2,499 points)

In an equilateral △ABC of side 14 cm, side BC is the diameter of a semi-circle as shown in the figure below. Find the area of the shaded region. (Take π = 22/7 and √3 = 1.732)  

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answered Mar 18 by aditya23 (-854 points)

Area of shaded part = Area of equilateral △ABC + Area of semi circle

= √3/4 a2 + 1/2 πr2

Given  a = 14 cm and r = 14/2 = 7 cm

∴   Area of shaded part = √3/4 × 142 + ½ × 22/7 × 7 × 7

= (1.732 × 14 × 14)/4 + 11 × 7

= 1.732 × 7 × 7 + 77 = 84.868 + 77

= 161.868 sq. cm.

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