The diameter of the cross section of a water pipe is 5 cm.

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asked Mar 27 in Class X Maths by muskan15 (-3,437 points)

The diameter of the cross section of a water pipe is 5 cm. Water flows through it at 10km/hr  into a cistern in the form of a cylinder. If the radius of the base of the cistern is 2.5 m, find the height to which the water will rise in the cistern in 24 minutes.

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answered Mar 27 by navnit40 (-4,746 points)

Area of the cross section of the water pipe = πr2

= 3.142 × 5/2 × 5/2

Speed of water = 10 km/hr

= (10 × 1000 × 100)/60 cm/minutes

∴   Quantity of water supplied in 24 minutes = 3.142  × 5/2 × 5/2 × 100000/6 × 24

= 7855000 cm3

Let the height of water in the cistern be h cm.

The quantity of water collected in the cistern = 3.142  × 250 × 250 × h cm3

Both the above quantities must be equal

∴    3.142 × 250 × 250 × h = 7855000

h =  7855000 × (1/3.142 × 250 × 250)

= 40 cm 

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