A group of labourers promises to do a piece of work in 10 days, but five of them become absent.

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asked May 15 in Class VIII Maths by aditya23 (-1,702 points)

A group of labourers promises to do a piece of work in 10 days, but five of them become absent. If the remaining labourers complete the work in 12 days, find their original number in the group.

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answered May 15 by muskan15 (-3,360 points)

Total period = 10 days
But work completed in = 12 days
No. of men were absent = 5
Let the number of men in the beginning = x
Now x men can do a piece work in = 10 days
1 man will do it in = 10x x days

And (x – 5) will do it in = (10 × x)/(x – 5) days

∴ 10x/(x – 5) = 12 ⇒ 10x = 12x – 60

⇒ 12x – 10x = 60 ⇒ 2x = 60

⇒ x = 60/2 = 30

∴ No. of men in the beginning = 30

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