Ten men working for 6 days of 10 hours each finish \frac { 5 }{ 21 } of a piece of work.

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asked May 15 in Class VIII Maths by aditya23 (-1,702 points)

Ten men, working for 6 days of 10 hours each, finish 5/21 of a piece of work. How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 days ?

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answered May 15 by muskan15 (-3,360 points)

Work do one = 5/21

Remaining work = 1- (5/2) = 16/21

5/21 of a work can be done in 6 days working

10 hours a day by = 10 m

1 work can be done in 6 days working 10 hours a day by = (10 × 21)/5

1 work can be done in 1 day working 10 hours day by = (10 × 21 × 6)/5 men

16/21 work can be done in 8 days working 10 hours a day by = (10 × 21 × 6 × 16)/(5 × 21 × 8) = 24 men

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