In \frac { 5 }{ 7 } xy2z3, write the coefficient of : 5

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asked May 15 in Class VIII Maths by aditya23 (-1,733 points)

In 5/7 xy2z3, write the coefficient of

(i) 5

(ii) 5/7

(iii) 5x

(iv) xy2

(v) z3

(vi) xz3

(vii) 5xy2

(viii) (1/7) yz

(ix) z

(x) yz2

(xi) 5xyz

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1 Answer

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answered May 15 by navnit40 (-4,280 points)

In 5/7 xy2z3, C0- efficient of

(i) 5 is 1/7 xy2z3

(ii) 5/7 is xy2z3

(iii) 5x is (1/7) y2z3

(iv) xy2 is (5/7) z3

(v) z3 is (5/7) xy2

(vi) xz3 is (5/7) y2

(vii) 5xy2 is 1/7 z3

(viii) 1/7 yz is 5xyz2

(ix)  z is 5/7 xy2z2

(x) yz2 is 5/7 xy – z

(xi) 5xyz is 1/7 yz2

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