In 5/7 xy^{2}z^{3}, C0- efficient of
(i) 5 is 1/7 xy^{2}z^{3}
(ii) 5/7 is xy^{2}z^{3}
(iii) 5x is (1/7) y^{2}z^{3}
(iv) xy^{2 }is (5/7) z^{3}
(v) z^{3} is (5/7) xy^{2}
(vi) xz^{3} is (5/7) y2
(vii) 5xy^{2} is 1/7 z^{3}
(viii) 1/7 yz is 5xyz^{2}
(ix) z is 5/7 xy^{2}z^{2}
(x) yz^{2} is 5/7 xy – z
(xi) 5xyz is 1/7 yz^{2}