The sides of a triangle are x2 – 3xy + 8, 4x2 + 5xy – 3 and 6 – 3x2 + 4xy.

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asked May 16 in Class VIII Maths by muskan15 (-2,329 points)

The sides of a triangle are x2 – 3xy + 8, 4x2 + 5xy – 3 and 6 – 3x2 + 4xy. Find its perimeter.

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1 Answer

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answered May 16 by priya12 (-11,279 points)

Required perimeter = Sum of three sides

= x2 – 3xy + 8 + 4x2 + 5xy – 3 + 6 – 3x2 + 4xy

= x2 + 4x2 – 3x2 – 3xy + 5xy + 4xy + 8 – 3 + 6

= 2x2 + 6xy + 11

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