The perimeter of a triangle is 8y2 – 9y + 4 and its two sides are 3y2 – 5y and 4y2 + 12.

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asked May 16 in Class VIII Maths by priya12 (-12,269 points)

The perimeter of a triangle is 8y2 – 9y + 4 and its two sides are 3y2 – 5y and 4y2 + 12. Find its third side.

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1 Answer

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answered May 16 by navnit40 (-4,290 points)

Perimeter of the triangle = Sum of three sides

= 8y2 – 9y + 4

Sum of two sides = 3y2 – 5y + 4y2 + 12

= 7y2 – 5y + 12

∴ (8y2 – 9y + 4) – (7y2 – 5y + 12)

= 8y2 – 9y + 4 – 7y2 + 5y – 12

= y2 – 4y – 8

Hence third side = y2 – 4y - 8

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