The adjacent sides of a rectangle are x2 – 4xy + 7y2 and x3 – 5xy2.

0 votes
1 view
asked May 16 in Class VIII Maths by muskan15 (-2,329 points)

The adjacent sides of a rectangle are x2 – 4xy + 7y2 and x3 – 5xy2. Find its area.

Please log in or register to answer this question.

1 Answer

0 votes
answered May 16 by priya12 (-11,279 points)

Reqd. area =  (x2 – 4xy + 7y2) (x3 – 5xy2)

= x2(x3 – 5xy2) – 4xy (x3 – 5xy2) + 7y2 (x3 – 5xy2)

= x5 – 5x3y2 – 4x4y + 20x2y3 + 7x3y2 – 35xy4

= x5 + (7 – 5)x3y2 – 4x4y + 20x2y3 – 35xy4

= x5 + 2x3y2 – 4x4y + 20x2y3 – 35xy4

= (x5 – 4x4y + 2x3y2 + 20x2y3 – 35xy4) sq. unit.

Related questions

...