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in Class VII Maths by (-3,443 points)

In the given figure, prove that:
∆ABD  ∆ ACD

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Proof :

In ∆ ABD and ∆ ACD,

AD = AD (common)

AB = AC (given)

BD = DC (given)

∴ ∆ ABD ≅ ∆ ACD (S.S.S Axiom)

Hence proved

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