In the given figure prove that:(i) PQ = RS(ii) PS = QR
Proof : In △PQR and △ PSR,
PR = PR (Common)
∠PRQ = ∠RPS (given)
∠PQR = ∠PSR (given)
∴ △ PQR ≅ △ PSR (A.A.S. Axiom)
Hence, (i) PQ = RS (c.p.c.t)
(ii) QR = PS (c.p.c.t)
Or PS = QR
Hence proved.