In the given figure, prove that:(i) ∆ABC ≅ ∆ DCB(ii) AC = DB
Proof:
In △ABC and △DCB,
CB = CB (common)
∠ABC = ∠BCD (each 90°)
and AB = CD (given)
(i) ∴ △ ABC ≅ △DCB (S.A.S. Axiom)
(ii) Hence AC = DB (c.p.c.t.)
Hence proved.