Length = 30 m
Diagonals = 34 m
Let the breadth of the rectangle = b m
Applying Pythagoras Theorem in triangle
ABC,
We get,
AC^{2} = AB^{2} + BC^{2}
(34)^{2} = (30)^{2} + b^{2}
1156 = 900 + b^{2}
1156 – 900 = b^{2}
256 = b^{2}
⇒ b = √256 = 16 m
Perimeter = 2 (l + b)
= 2(30 + 16) = 2 × 46 = 92 m