Length of a rectangle (l) = 24 cm Diagonal = 25 cm
Let breadth of the rectangle = b m
Applying Pythagoras Theorem in triangle ABC,
We get, (AC)^{2} = (AB)^{2} + (BC)^{2}
(25)^{2 }= (24)^{2} + (b)^{2}
625 = 576 + (b)^{2}
625 – 576 = b^{2}
49 = A2
√7x7 = b
∴ b = 7 cm
Now, perimeter of the rectangle
= 2(l + b)
= 2(24 + 7)
= 2(31)
= 62 cm