Solve each of the following equations : 3z – 18 = z – (12 - 4z)

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asked Jul 12 in Class VI Maths by navnit40 (-3,354 points)

Solve each of the following equations : 3z – 18 = z – (12 - 4z) 

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answered Jul 12 by muskan15 (-2,581 points)

3z – 18 = z – (12 – 4z)

⇒ 3z – 18 = z – 12 + 4z

⇒ 3z – 18 = 5z – 12

⇒ 3z – 18 + 18 = 5z - 12 + 18

(Adding 18 to both sides)

⇒ 3z = 5z + 6 – 5z

⇒ 3z – 5z = 5z + 6 – 5z

(Subtracting 5z from both sides)

⇒ -2z = 6

⇒ -2z/-2 = 6/-2 (Dividing by -2)

⇒ z = -3

∴ z = -3

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